(6x^-3/7y^-1)^-2

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Solution for (6x^-3/7y^-1)^-2 equation: 


D( x )

x = 0

((6*x^-3)/7)*y^-1 = 0

x = 0

x = 0

((6*x^-3)/7)*y^-1 = 0

((6*x^-3)/7)*y^-1 = 0

6/7*x^-3*y^-1 = 0 // : 6/7*y^-1

x^-3 = 0

x należy do O

x in (-oo:0) U (0:+oo)

(((6*x^-3)/7)*y^-1)^-2 = 0

49/36*x^6*y^2 = 0 // : 49/36*y^2

x^6 = 0

x = 0

x in { 0} 

x belongs to the empty set

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